MATLAB: How to remove the index number

removing the index number

Could anybody help me how to remove the index number in for loop for the code mentioned below under the scenario it should not get repeated again in other group and for each run the matrix A should be updated.

A = diag([1 2 3 4 5 6 7 8 9 10 11 12 13 14 15]);
N_G=4;%No of group
B = cell(N_G,1);
sumB = cell(N_G,1);
%

for i=1:1:N_G
    n=randi([1 15],1)% select No of UE randomly 
    idx=randsample(1:size(A,2),n)
    B{i} = A(idx,:)
    %
    [rows, columns] = size(B{i})
    % Get sum of columns and replicate vertically.
    sumB{i} = repmat(sum(B{i}, 1), [rows, 1])
end

Best Answer

It's not clear what you mean. A for loop has to have an index (loop iteration variable), though you're free to use it or ignore it in the loop. Also if you want A to change (somehow) in the loop, you're going to have to have A on the left side of an equals sign.

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MATLAB: Random grouping of users and subcarriers

Change this line

G = rand(s,p)

to this

G=[randsample(N_SC(r),1) randsample(N_UE(p),1)]

MATLAB: How grouping of users can be done

Is this what you want?

numUsers = 50;
N_UE = 1 : numUsers
% Get a scrambled array
s = N_UE(randperm(length(N_UE)))
numGroups = 5; % Need to divide s up into 5 groups
divisions = sort(randperm(numUsers-2, numGroups-1) + 1, 'ascend')
divisions = [0, divisions, numUsers]
% Create cell array with random number of users in each groups
groups = cell(1, numGroups);
for k = 1 : numGroups
  indexes = divisions(k)+1:divisions(k+1);
  % Assign users to the kth group:
  usersInThisGroups = length(indexes);
  fprintf('Assigning %d users (indexes %d to %d) to group %d.\n', ...
    usersInThisGroups, divisions(k)+1,divisions(k+1), k);
  groups{k} = s(indexes);
end
celldisp(groups); % Display groups in command window.

You'll see

Assigning 19 users (indexes 1 to 19) to group 1.
Assigning 5 users (indexes 20 to 24) to group 2.
Assigning 7 users (indexes 25 to 31) to group 3.
Assigning 9 users (indexes 32 to 40) to group 4.
Assigning 10 users (indexes 41 to 50) to group 5.
groups{1} =
  20    17    10    12     4     9    32    13    50    49    23    15    41    26    37    28     6    47    43
groups{2} =
  22    31     7    35    29
groups{3} =
  18    11     8    44    42    38    46
groups{4} =
  30    36    33    24    19     2    45     5    34
groups{5} =
  21     1    16    39    14    27    48    40     3    25

You have 5 groups and in each group is a random number of users chosen from the entire group of 50 users. The users in each group are randomly chosen (not sequentially taken) from the larger, entire group of 50. Every user is in exactly one and only one group, and no user is missing. Change numUsers and numGroups as needed for your situation.

Best Answer

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MATLAB: Random grouping of users and subcarriers

MATLAB: How grouping of users can be done

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