MATLAB: How to produce an ‘if else’ loop with an x starting at 1 and increasing to 3 by 1 at each end of the loop

if loop

x = [1:1:3];

if x == 2; f2 = inf elseif x > 2; f2 = NaN else f2 = log(5/2-x) end

I'm trying to input a value of x = 1, then x = 2, then x = 3 to get three different answers

Best Answer

if x == 1; 
    f2 = inf 
elseif x == 2; 
    f2 = NaN 
elseif x ==3
    f2 = log(5/2-x) 
end

As Roger Stafford said, third case will be complex.

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MATLAB: How to use ‘if else’ in this case

See the description of the second output from the chol function on its documentation page.

MATLAB: How to make simpler this at ‘if condition’

I am not certain this is more efficient than your code, however it takes advantage of the repeating patterns to make it simpler:

a = randi(9, 6, 9);                                                 % Create ‘a’
C1 = 4 : 4 : 32;
ahatfcn = @(k) [a(1,k),a(2,k),a(3,k),a(4,k),a(5,k),a(6,k)];         % Create Anonymous Function
for ii = 1 : 40                                                     % Loop Over ‘ii’
    if ii < 5
        ahat = ahatfcn(1);
    else
        for k1 = 1:numel(C1)
            if ((C1(k1)<ii) && (ii<(C1(k1)+5)))
                ahat = ahatfcn(k1+1);
            end
        end
    end
end
a = ahat

It runs without error. I defer to you to determine if it produces the result you want.

Best Answer

Related Solutions

MATLAB: How to use ‘if else’ in this case

MATLAB: How to make simpler this at ‘if condition’

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