MATLAB: How to pre-allocate a struct in Matlab

pre-allocationstruct

I want to pre-allocate stuct e1 and struct e3 in the following loop. I would be thankfull if someone can help.
clc;
clear;
close all; 
x=[-30;-25;-20;20;25;30;30;25;20;-20;-25;-30];
y=[-25;-25;-25;-25;-25;-25;25;25;25;25;25;25];
 i=x(1:end);
 j=y(1:end);
M=[i,j];
s.x=[];
s.y=[];
c=repmat(s,12,1);
c(1).x=M(1,1);
c(1).y=M(1,2);
c(2).x=M(2,1);
c(2).y=M(2,2);
c(3).x=M(3,1);
c(3).y=M(3,2);
c(4).x=M(4,1);
c(4).y=M(4,2);
c(5).x=M(5,1);
c(5).y=M(5,2);
c(6).x=M(6,1);
c(6).y=M(6,2);
c(7).x=M(7,1);
c(7).y=M(7,2);
c(8).x=M(8,1);
c(8).y=M(8,2);
c(9).x=M(9,1);
c(9).y=M(9,2);
c(10).x=M(10,1);
c(10).y=M(10,2);
c(11).x=M(11,1);
c(11).y=M(11,2);
c(12).x=M(12,1);
c(12).y=M(12,2); 
for i=1:27
    j=c(2);
    k=c(4);
    l=c(7);
    o=c(10);
    e3(i,:)=[j;k;l];
    
    for i=1:3:25
        o=c(10);
        e1(i,:)=o;
    end
    
    for i=2:3:26
        o=c(11);
        e1(i,:)=o;
        
    end
    
    for i=3:3:27
        o=c(12);
        e1(i,:)=o;
    end
    
    
    for i=4:6
        k=c(5);
        e3(i,:)=[j;k;l];
    end
    for i=7:9
        k=c(6);
        e3(i,:)=[j;k;l];
        
    end
    
    for i=10:18
        l=c(8);
        e3(i,:)=[j;k;l];
    end
    
    for i=13:15
        k=c(5);
        e3(i,:)=[j;k;l];
        
    end
    
    for i=16:18 %#ok<*FXSET>
        k=c(6);
        d3(i,:)=[j;k;l];
        
    end
    for i=19:27
        l=c(9);
        e3(i,:)=[j;k;l];
        
        
        for i=22:24
            k=c(5);
            e3(i,:)=[j;k;l];
        end
        
        for i=25:27
            k=c(6);
            e3(i,:)=[j;k;l];
        end
        
        
    end
    e=[e3,e1];
  end

Best Answer

Did you mean memory pre-allocation? if so, then
e1=zeros(27,1); 
e3=ones(27,3);
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