MATLAB: How to plot the function f(x)=x^3 – 4x^2 +1 for x∈[0,25]

plot a graph

x= 0:0.01:25. For y=x^3 – 4x^2 +1 your plot command will be variant of plot(x,y).

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You almost got it. Since x is a vector, you should use elementwise operators. not x^2 (what's the square of a vector?) but x.^2.

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MATLAB: How do i plot x^2 +4y^2 +9z^2 = 1

fimplicit3(@(x,y,z) x.^2 +4*y.^2 +9*z.^2 - 1)

MATLAB: Plot +1 +1 -1 -1 rectangular pulse

Previously the pattern was repeating after every 2 occasions (+1 -1)(+1 -1). So, you used rem function with respect to 2. Now the pattern has to repeat after every 4 occasions (+1 +1 -1 -1)(+1 +1 -1 -1). So, let us use rem function with respect to 4. I think the changes as done below will suffice your requirement.

for m = 0:Npulses
  if  rem(m,4) == 0 | rem(m,4) == 1  %1st and 2nd term
        Tx1 = exp(1j*pi*gamma*(t-m*PRI).^2);
        W=ones(size(t));
        W(t<m*PRI)=0; 
        W(t>(m*PRI+tau))=0; 
        s1 = Tx1.*W+s1;
      else
          Tx2 = -exp(1j*pi*gamma*(t-m*PRI).^2);
          W=ones(size(t));
          W(t<m*PRI)=0;
          W(t>(m*PRI+tau))=0;
          s1 = Tx2.*W+s1;
      end
end

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MATLAB: How do i plot x^2 +4y^2 +9z^2 = 1

MATLAB: Plot +1 +1 -1 -1 rectangular pulse

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