Hi every one;
I am going to attempt that query:
Write a function called June2015 that returns a cell array of dimensions 30-by-3, whose rows correspond to the days of June, 2015. The three elements of each row must be set as follows:
• The first element refers to the string 'June' (uppercase ‘J’). • The second element refers to a scalar of type double that equals the date (1 through 30). • The third element refers to the three-letter abbreviation of the day chosen from this list: 'Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat', 'Sun'.
For example, here is a call of the function followed by a command that shows the eleventh element of the cell array that is returned by the function:
>> m = June2015;>> m(11,:)ans ='June' [11] 'Thu'
I am using that code
function m = June2015A=cell(30,3)%declar cell array of 30 by 3
for i = 1:30 [DateNumber, DateName] = weekday(datenum([2015 6 i]));% making the value of DateNume for DateNumber
%and loop run number of rows in cell array
for j=1:3% loop run for column of cell array
A(i,:)={'June', i, 'DateName'} endendend
but in testing i am getting that error
Your solution is _not_ correct.
Guide me about my corrections.. thanks in advance
Best Answer