MATLAB: How to graph discrete equation: y(n) = y(n-1) + 1 for 1000 samples

discrete

I need to graph this equation, and I have no idea how to, because as soon as I declare y(n) = y(n-1) + 1, it throws results until 1000+ not having any regards of the n value.
Code used:
      n = 1;
      x = [];
      y (1) = 1;
      while n <= 1000;
                n = n+1;
                x = [n,y];
                y(n) = y(n-1) + 1;
      end
      stem(x);

Best Answer

I would do something like this:
%create a vector of the correct size
y=NaN(1000,1); % by using NaN we should notice it if we skip a value
y(1) = 1;
for n=2:numel(y)
    y(n)=y(n-1)+1;
end
%now we have a vector we can plot:
plot(y,'*')
In this case we could have taken a shortcut:
y=ones(1000,1);
y=cumsum(y);
plot(y,'*')
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