I have the following code.
%%
E=200e9; I=7.999e-5; K=-1/(E*I); x=[0:0.1:25]; vv=[];
for i=0:0.1:25
B=[ 0 0 0 0 0 0 0 1 ; 125/6 0 0 0 0 0 5 1 ; 500/3 125/6 0 0 0 0 10 1 ; 1125/2 500/3 125/6 0 0 0 15 1 ; 4000/3 1125/2 500/3 125/6 0 0 20 1 ; 15625/6 4000/3 1125/2 500/3 125/6 0 25 1 ; 1 1 1 1 1 1 0 0 ; 25 20 15 10 5 0 0 0 ]; c=[0 ; (98100./6).*(max(5-i,0)).^3 ; (98100./6).*(max(10-i,0)).^3 ; (98100./6).*(max(15-i,0)).^3 ; (98100./6).*(max(20-i,0)).^3 ; (98100./6).*(max(25-i,0)).^3 ; 98100 ; 98100.*(25-i)]; z=B\c; % The Values of all of the Reaction Forces and Integration Constants are as follows:
Ra = z(1); Rb = z(2); Rc = z(3); Rd = z(4); Re = z(5); Rf = z(6); C1 = z(7); % Integration Constand
C2 = z(8); % Integration Constand V=K.*(Ra.*((max(x,0)).^3)./6+Rb.*((max(x-5,0)).^3)./6+Rc.*((max(x-10,0)).^3)./6+Rd.*((max(x-15,0)).^3)./6+Re.*((max(x-20,0)).^3)./6-98100.*(((max(x-i,0))).^3)./6 + C1.*x + C2); vv=[vv;V];end
p=[0:0.1:25];
% Generate coordinate pairs [X,P]=meshgrid(x,p); figure(100) surf(X,P,vv);
% % Evaluate function on grid
% Plot surface shading interp; hold on xlabel('Beam Length (m)') ylabel('Crane Position (m)') zlabel('Deflection (m)') hold off
[Zmax,Idx] = max(vv(:)) [ZmaxRow,ZmaxCol] = ind2sub(size(vv), Idx)
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I need the x and y value for a specific max z. How do I get it? I have the position in the matrix for the max z but not the value of x and y at that max z. then how doe you find 2 * max z values if your plot shows two values?
Please help me if you can?
Best Answer