MATLAB: How to generate the rest of elements of a matrix if only the first row and first column of the matrix is known

Suppose I have a matrix of N*N whose first row is, say [0 10 20 30] and first column is [ 0 5 10 15 ] and now i want to genetare the rest of the marrix of order 4*4 only with the help of the row and column mentioned above.

P.S : The elements should be calculated diagonally corresponding to each and every element of row and column.

for example, a22 = sqrt(a12^2 + a21^2), a23 = sqrt(a13^2 +a21^2) and so on……

and, a32 = sqrt(a12^2 + a31^2), a33 = sqrt(a13^2 + a31^2) so on….

and same trend follows for the rest of the elements.

Best Answer

sqrt(bsxfun(@plus, column(:).^2, row.^2))

Related Solutions

MATLAB: Strfind first occurrence.

You could use regexp with the 'once' option:

k = regexp(str, 'in', 'once')

However, note that some characters have special meanings in regular expression, so if your search string is completely arbitrary you can't just replace strfind with regexp. For safety you can regexptranslate the search string.

On the other hand, what's stopping you from writing:

k = strfind(str, 'in); k = k(1);

If writing two instructions instead of one bother you, you can always create your own function:

function location = strfindfirst(lookin, lookfor)
   location = strfind(lookin, lookfor);
   if ~isempty(idx)
      location = location(1);
   end
end

MATLAB: Comparing first n digits

[tf, Bidx] = ismember(fix(A/10), B);

Now, tf(K) tells you whether A(K) had a match in B or not, and if tf(K) is true then Bidx(K) tells you which entry in B matched.

Best Answer

Related Solutions

MATLAB: Strfind first occurrence.

MATLAB: Comparing first n digits

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