MATLAB: How to fix the meshgrid

Question

This is the code i have inserted and im getting this. Where is the mistake in my coding and how do I fix this?

gridspacing=-8:0.5:8;

Y=-8:0:8;

Z=-8:1.5:8;

[x,Y] = meshgrid (-8:0.5:8);

Z=sqrt(exp(-x.^2-Y.^2))

surf(x,Y,Z,x.*exp(Y))

Z(R==0)=1

z = sin (R)/R

Answer 1

Hi! Thanks for providing extra details! Below are the steps I used with explanations for each. I also labeled them in accordance with the steps in the instructions you provided.

close all; clear all; clc; %close all open figure windows, clear the variables, and clear the command window
%Step 1:
gridspacing = -8: 0.5: 8; %setup the grid spacing vector that will be used to make the meshgrid
[X Y]=meshgrid(gridspacing); %create the mesh grid
%Step 2:
R=sqrt(X.^2 + Y.^2); %Create a 2D set of values from the X and Y grids created with meshgrid

In the instructions you provided, it says that R=X^2 + Y^2. If you use this equation, you get a plot that does not match the figure you have provided. If you use the R equation in the instructions, you do get the right answers. Additionally, it says to treat X and Y like vectors. I think by this they're hinting that you should use element-wise powers (.^ rather than ^) on the matrices, not use vectors for x and y.

%Step 3:
Z=sin(R)./R; %use element-wise division to do this calculation on each grid point
Z(R==0)=1; %in any location that R is equal to 0, set Z=1
%Step 4:
figure;
mesh(x,y,Z); %surf gives you a similar plot but it's shaded in rather than a wire mesh. 

The default colormap is going to be perula, while it looks like the colormap for the example figure you show is jet. You can easily change this with one line of code after you use the mesh function:

colormap('jet');

Hope this helps!