For the intersection value aijk, how do I find the (x,y) coordinate in PCi, PCj, and PCk (circle powers for i, j, and k respectively) that produce PCi=PCj=PCk (the value aijk)? Circle Power For 3 intersecting circles as in the plot, the Circle power will be at the point of intersection of all 3 chords (seen in image below).
clc clear all xCenterk = 5; yCenterk = 2; xCenteri = 5; yCenteri = 5; xCenterj = 3; yCenterj = 3; radiusk = 1.5; radiusi = 2; radiusj = 1.5;theta = 0 : 0.01 : 2*pi; x=0:.001:100; y=0:.001:100;%%%section my question is about
PCi= (x-xCenteri).^2+(y-yCenteri).^2-radiusi.^2; PCj= (x-xCenterj).^2+(y-yCenterj).^2-radiusj.^2; PCk= (x-xCenterk).^2+(y-yCenterk).^2-radiusk.^2; aij=(intersect(PCi,PCj)); aik=(intersect(PCi,PCk)); aijk=intersect(aij,aik); %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
%%%plot for visual reference
xk = radiusk * cos(theta) + xCenterk; yk = radiusk * sin(theta) + yCenterk; xi = radiusi * cos(theta) + xCenteri; yi = radiusi * sin(theta) + yCenteri; xj = radiusj * cos(theta) + xCenterj; yj = radiusj * sin(theta) + yCenterj; plot(xk, yk,'b.',xi,yi,'r.',xj,yj,'c.'); hold on axis equal;
Best Answer