MATLAB: How to find solution of higher order equations for a number of Values

equation

I want to find the solution of (r^2)/sqrt((1-r^2)^2+4*1.44*r^2) for all the values of 'r' between (0-5) with an increment of 0.01 . I was using:

r=0:0.01:5;

y=(r^2)/sqrt((1-r^2)^2+4*1.44*r^2)

But it kept on saying that:

??? Error using ==> mpower Inputs must be a scalar and a square matrix. To compute elementwise POWER, use POWER (.^) instead".

I want to know that how can i find the solution to this problem. Please help me out here.

Thanks,

Danish

Best Answer

It keeps saying that because it’s doing its best to give you the solution to your problem. I can’t improve on its advise.

Related Solutions

MATLAB: Taylor’s method of order 2 programming

See if vectorising this line (replacing (/) with (./) and (*) with (.*)) solves the problem:

truesol= (sqrt(3)./(2*t)).*tan((sqrt(3)/2)*log(t))-1/2*t;

Consider vectorising other lines in your code as well. See Array vs. Matrix Operations for details.

MATLAB: When I run the program inaccurate results appear What is the problem

The best approach to this is likely not the vpasolve function, since it takes forever.

I have no idea of these are the ‘accurate’ results you want (I have no idea what that means), however you will get them much more quickly:

syms t y1 y2 y3 y4  yn11 yn1 yr yr11 yr111   yr v y(v) x
format longe
h=0.1;
r=1.7686999343761197980595002942562;   %1694/911=1.859495060373216e+00
x=0;
y0=0;
y01=0.25;
y011=0;
fn=-y01+y0.*y01.*y011;
fnr=-yr11+yr.*yr11.*yr111;
fn1=-yn1+y1.*yn1.*yn11;
fn2=-y3+y2.*y3.*y4;
eq1 =-y2-(r - 2)/r*y0+ 2/(r*(r - 1))*yr+ (2*r - 4)/(r - 1)*y1 -(h.^3.*(r^4 - 8*r^3 + 22*r^2 - 23*r + 6))/(120*r)*fn+ (h.^3.*(- r^2 + 2*r + 3))/(60*r)*fnr -(h.^3.*(- r^3 + 4*r^2 + 9*r - 26))/60*fn1+ (h.^3.*(- r^3 + 2*r + 1))/120*fn2;
eq1 = simplifyFraction(eq1);
eq1d = vpa(eq1, 5)
eq2= -h.*y3 -(r - 3)/r*y0+ 3/(r*(r - 1))*yr+ (r - 4)/(r - 1)*y1 -(h.^3.*(3*r^4 - 24*r^3 + 66*r^2 - 67*r + 12))/(240*r)*fn -(h.^3.*(r^4 - 5*r^3 + 5*r^2 + 5*r - 4))/(40*r*(r^2 - 3*r + 2))*fnr -(h.^3.*(- 3*r^4 + 15*r^3 + 15*r^2 - 137*r + 116))/(120*(r - 1))*fn1+ (h.^3.*(- r^4 + 2*r^3 + 2*r^2 + 3*r - 12))/(80*(r - 2))*fn2;
eq2 = simplifyFraction(eq2);
eq2d = vpa(eq2, 5)
eq3=-h.^2.*y4+2/r*y0+ 2/(r*(r - 1))*yr -2/(r - 1)*y1+ (h.^3.*(- r^4 + 8*r^3 - 22*r^2 + 18*r + 5))/(120*r)*fn -(h.^3.*(r^4 - 5*r^3 + 5*r^2 + 5*r + 5))/(60*r*(r^2 - 3*r + 2))*fnr -(h.^3.*(- r^4 + 5*r^3 + 5*r^2 - 75*r + 77))/(60*(r - 1))*fn1+ (h.^3.*(- r^4 + 2*r^3 + 2*r^2 + 42*r - 81))/(120*(r - 2))*fn2;
eq3 = simplifyFraction(eq3);
eq3d = vpa(eq3, 5)
eq4=-h.*yn1 -(r - 1)/r*y0+ 1/(r*(r - 1))*yr+ (r - 2)/(r - 1)*y1 -(h.^3.*(r^4 - 8*r^3 + 22*r^2 - 21*r + 6))/(240*r)*fn+ (h.^3.*(- r^2 + 2*r + 3))/(120*r)*fnr -(h.^3.*(- r^3 + 4*r^2 + 9*r - 8))/120*fn1 -(h.^3.*(r^3 - 2*r + 1))/240*fn2;
eq4 = simplifyFraction(eq4);
eq4d = vpa(eq4, 5)
eq5=-h.^2.*yn11+ 2/r*y0+ 2/(r*(r - 1))*yr -2/(r - 1)*y1 -(h.^3.*(r^4 - 8*r^3 + 22*r^2 - 28*r + 10))/(120*r)*fn -(h.^3.*(r^4 - 5*r^3 + 5*r^2 + 5*r - 10))/(60*r*(r^2 - 3*r + 2))*fnr -(h.^3.*(- r^4 + 5*r^3 + 5*r^2 - 35*r + 22))/(60*(r - 1))*fn1+ (h.^3.*(- r^4 + 2*r^3 + 2*r^2 - 8*r + 4))/(120*(r - 2))*fn2;
eq5 = simplifyFraction(eq5);
eq5d = vpa(eq5, 5)
eq6=-h.*yr11+ (r - 1)/r*y0+ (2*r - 1)/(r*(r - 1))*yr -r/(r - 1)*y1+ (h.^3.*(2*r^4 - 13*r^3 + 28*r^2 - 22*r + 5))/240*fn+ (h.^3.*(4*r^3 - 15*r^2 + 10*r + 5))/(120*(r - 2))*fnr+ (h.^3.*r*(- 2*r^3 + 7*r^2 + 2*r - 3))/120*fn1+ (h.^3.*r*(2*r^4 - 5*r^3 + 2*r^2 + 2*r - 1))/(240*(r - 2))*fn2;
eq6 = simplifyFraction(eq6);
eq6d = vpa(eq6, 5)
eq7=-h.^2.*yr111+ 2/r*y0+ 2/(r*(r - 1))*yr -2/(r - 1)*y1+ (h.^3.*(4*r^4 - 22*r^3 + 38*r^2 - 22*r + 5))/(120*r)*fn -(h.^3.*(- 14*r^4 + 55*r^3 - 55*r^2 + 5*r + 5))/(60*r*(r^2 - 3*r + 2))*fnr -(h.^3.*(4*r^4 - 15*r^3 + 5*r^2 + 5*r - 3))/(60*(r - 1))*fn1+ (h.^3.*(4*r^4 - 8*r^3 + 2*r^2 + 2*r - 1))/(120*(r - 2))*fn2;
eq7 = simplifyFraction(eq7);
eq7d = vpa(eq7, 5)
eq8=-h.*y01 -(r + 1)/r*y0 -1/(r*(r - 1))*yr+ r/(r - 1)*y1+ (h.^3.*(r^3 - 8*r^2 + 22*r - 5))/240*fn+ (h.^3.*(r^3 - 5*r^2 + 5*r + 5))/(120*(r^2 - 3*r + 2))*fnr+ (h.^3.*r*(- r^3 + 5*r^2 + 5*r - 3))/(120*(r - 1))*fn1 -(h.^3.*r*(- r^3 + 2*r^2 + 2*r - 1))/(240*(r - 2))*fn2;
eq8 = simplifyFraction(eq8);
eq8d = vpa(eq8, 5)
eq9 =-h.^2.*y011+ 2/r*y0+ 2/(r*(r - 1))*yr -2/(r - 1)*y1 -(h.^3.*(r^4 - 8*r^3 + 22*r^2 + 22*r - 5))/(120*r)*fn -(h.^3.*(r^4 - 5*r^3 + 5*r^2 + 5*r + 5))/(60*r*(r^2 - 3*r + 2))*fnr -(h.^3.*(- r^4 + 5*r^3 + 5*r^2 + 5*r - 3))/(60*(r - 1))*fn1+ (h.^3.*(- r^4 + 2*r^3 + 2*r^2 + 2*r - 1))/(120*(r - 2))*fn2;
eq9 = simplifyFraction(eq9);
eq9d = vpa(eq9, 5)
eqsfcn = matlabFunction([eq1,eq2,eq3,eq4,eq5,eq6,eq7,eq8,eq9], 'Vars',{[y1,y2,y3,y4,yn1,yn11,yr,yr11,yr111]})
eqsol = fsolve(eqsfcn, rand(1,9))
eqsolc = num2cell(eqsol);
[y1,y2,y3,y4,yn1,yn11,yr,yr11,yr111] = eqsolc{:}

I used the simplifyFraction function to do just that with your equations, then the fsolve function to do the actual calculations. These changes make it significantly more efficient.

The results I got are:

y1 =
     2.495835158216658e-02
y2 =
     4.966725033036157e-02
y3 =
     2.450145921764798e-01
y4 =
    -4.970810349993776e-02
yn1 =
     2.487509121241510e-01
yn11 =
    -2.496352514349295e-02
yr =
     4.398727143758653e-02
yr11 =
     2.460985502335340e-01
yr111 =
    -4.401564490668385e-02

You must be certain your equations are written as you want them to be in order to get ‘accurate’ values. We have no control over that.

Experiment to get the results you want.

Best Answer

Related Solutions

MATLAB: Taylor’s method of order 2 programming

MATLAB: When I run the program inaccurate results appear What is the problem

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