MATLAB: How to find solution for differential (dy/dx) for 2 conditions

differential equations

I want to solve a differential dy/dx for 2 conditions as x tends to infinity and x tends to zero. Is there any way I can do that in matlab

Best Answer

Hi it depends on the following two ways:

1. If it is a differential equation, you can use numerical methods (ODE45, etc) or analytical technique (solve) to solve the given differential equation.

2. If it is differential, then you have to provide the function 'y' i.e y = f(x); and then you can follow limit approach. To compute limit you can adopt symbolic approach (limit).

Related Solutions

MATLAB: How can i find the dy/dx of the differantial equation

"(My Code is correct)"

To me it's not. See below for the correction (the problem is I can't see it's change the solution after fixing the code, and I don't know why and did not investigated further for reason).

I give you here the code corrected + 2 methods to computs dy/dx

x1=0.06; x2=0.08;
xmesh = linspace(x1,x2);
solinit = bvpinit(xmesh, @guess);
sol= bvp5c( @heatcylinder1D, @bcfcn, solinit);
figure
hold on
plot(gradient(sol.y(1,:),sol.x),'ro-')
plot(deval(sol,sol.x,2)./sol.x,'b+-')
legend('dy/dx gradient','dy/dx deval')
function res = bcfcn(ya,yb)
res = [ya(1)-150
    yb(1)-60];
end
function g = guess(x)
g = [1 1000];
end
function dxdy = heatcylinder1D(x,y)
dxdy = zeros(2,1);
dxdy(1) = y(2)/x;
dxdy(2) = 10*x; % <= error is here
end

MATLAB: Just for clarification below is the question again (d^2 y)/(dx^2 )+4dy/dx+3y=0 subject to initial condition where dy/dx=4 and y=4. Can you help me explain how this can be solved

dsolve() or one of the ode* routines.

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Related Solutions

MATLAB: How can i find the dy/dx of the differantial equation

MATLAB: Just for clarification below is the question again (d^2 y)/(dx^2 )+4dy/dx+3y=0 subject to initial condition where dy/dx=4 and y=4. Can you help me explain how this can be solved

Related Question