MATLAB: How to find single index values in a matrix

matrix

B1 = [2 4 6 8; 10 12 14 16; 18 20 22 24; 26 28 30 32]
idx_8=find(B1==8)
[row,column]=find(B1~=8)
RowColumn = [row:column]

Find the single index values for 26, 4, and 28?

How is a matrix indexed with single indexing values?

Best Answer

https://in.mathworks.com/company/newsletters/articles/matrix-indexing-in-matlab.html - read it for better understanding

Linear_indices = find(ismember(B1,[26 4 28])); % you mean linear indices by saying single indices
B1(Linear_indices) % would give [26 4 28]

Related Solutions

MATLAB: Compare two columns and retrive joint values

[found, where] = ismember(B1, A1);   %note the order of the inputs!
assert(all(found), 'Some values of B1 not in A1');
C = [A2(where), B2]

MATLAB: Index search in nested structure

In the case where the name might occur multiple times and you want to locate all of them, and you are only searching for one name:

idx = find(ismember({obj.characteristic4.name}, NameToSearchFor))

idx could be empty if the name is not found

In the case where the name occurs at most once or you only care about the first of them

[wasfound, idx] = ismember(NameToSearchFor, ismember({obj.characteristic4.name})

wasfound will be true if the name was found. idx will be the corresponding index in obj.characteristic4

In both cases you can extend NameToSearchFor to a cell array of character vectors of names to look for. With one order of the arguments to ismember, you are looking to see whether each name like 'Tim' matches somewhere in the characteristic4 list, and with the other order of arguments to ismember, you are looking to see whether the entries in the characteristic4 list match something in the list of names. Both have their uses.

Best Answer

Related Solutions

MATLAB: Compare two columns and retrive joint values

MATLAB: Index search in nested structure

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