MATLAB: How to find elements in sequence in an array

array elementssequence

I have an array of numbers. I want to find set of numbers for which difference of two consecutive numbers is 1. For example, I have a sequence [2,3,6,8,9,10,12,14,16,17]. How can I extract position of (2,3), (8,9,10), (16,17)? I also want to save the output in a new array.

Best Answer

v=[2,3,6,8,9,10,12,14,16,17]
id=[10 diff(v) 10]==1
ii1=strfind(id,[0 1])
ii2=strfind(id,[ 1 0])

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MATLAB: How to do the following in a simpler and smarter way

C=repmat(1:21,12,1)
C=C(:)'

%or

C=1:21;
C=reshape(C(ones(12,1),:),1,[])

MATLAB: List the result of the index values in ranges

A = [1 1 2 2 3 3 2 2 1 1];
X = arrayfun(@(k) find(A==k),1:3,'un',0) ;
Y = cellfun(@(v) [v([true diff(v) > 1]) ; v([diff(v) > 1 true])]', X,'un',0) ;
% Y{k} contains the start indices (1st column) and end indices (2nd column) for a sequence of the value k in A

Best Answer

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MATLAB: List the result of the index values in ranges

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