MATLAB: How to evaluate this triple integral using the function integral3

triple integral

xmin= @(y) y.^2
xmax= @(y) y.^0.5
ymin=0
ymax=1
zmin=0
zmax=@(x,y,z) x+y+36
h = @(y,x,z) 1  %dz dx dy
answer3 = integral3(h, ymin, ymax , xmin , xmax , zmin, zmax);
answer3 = vpa(answer3,8)
%%why doesnt this code work, can someone help me

Best Answer

xmin= @(y) y.^2
xmin = function_handle with value:
    @(y)y.^2

xmax= @(y) y.^0.5
xmax = function_handle with value:
    @(y)y.^0.5

ymin=0
ymin = 0
ymax=1
ymax = 1
zmin=0
zmin = 0
zmax=@(x,y,z) x+y+36
zmax = function_handle with value:
    @(x,y,z)x+y+36

h = @(y,x,z) ones(size(y))  %dz dx dy
h = function_handle with value:
    @(y,x,z)ones(size(y))

answer3 = integral3(h, ymin, ymax , xmin , xmax , zmin, zmax);
answer3 = vpa(answer3,8)
answer3 = 
12.3
Related Question