MATLAB: How to do convolution Of this x1 and x10 function

convolution

fs=100;
Ts=1/fs;
t= [-1:Ts:3];
x1 = 2*rectpuls(t-0.5);
figure(1);
plot(t,x1);
axis ([-1 3 -1 3]);
xlabel ('time(sec)')
ylabel ('2rect(t-0.5)')
title ('f(t)')
x10 = 0.5*rectpuls(0.5*t -0.5);
figure(2);
plot(t,x10);
axis ([-1 3 -1 3]); 
xlabel ('time(sec)')
ylabel ('0.5rect(0.5t-0.5')
title ('g(t)')

Best Answer

result=conv(x1,x10);
plot(result);

Please do all other axes labeling and title

Related Solutions

MATLAB: Verification of system characteristics

% FOR TIME VARITANT OR INVARIANT
clc
clear all
close all
t=-5:0.001:5
l=length(t)
for i=1:l
    if t(i)>=0
        x1(i)=1;
        
    else x1(i)=0;
    end
end
x2=cos(pi*t)
x3=cos(pi*(t-2))
y1=x1.*x2
y2=x1.*x3
subplot(4,1,1)
plot(t,x1)
xlabel('t')
ylabel('x1')
title('for x1')
grid on
gtext('1841014009')
subplot(4,1,2)
plot(t,y1)
xlabel('t')
ylabel('y1')
title('for y1')
grid on
gtext('1841014009')
subplot(4,1,3)
plot(t,x2)
xlabel('t')
ylabel('x2')
title('for x2')
grid on
gtext('1841014009')
subplot(4,1,4)
plot(t,y2)
xlabel('t')
ylabel('y2')
title('for y2')
grid on
gtext('1841014009')
if round(y1)==round(y2)
    disp('time invariant');text(-2,-0.5, ('System Is Time Invariant'));
    
else disp('time variant');text(-2,-0.5, ('System Is Time Variant'))
end
% FOR LINEARITY TEST
clc
clear all
close all
t=-4:0.001:5
l=length(t)
for i=1:l
    if t(i)>=0
        x1(i)=1;
        
    else x1(i)=0;
    end
end
 
for i=1:l
if t(i)>=1
    x2(i)=1;
    
else x2(i)=0;
end
end
 
a1=2
a2=3
 
y1=a1.*x1.*cos(pi*t)
y2=a2.*x2.*cos(pi*(t-1))
 
y=((a1.*x1)+(a2.*x2)).*cos(pi*t)
 
y3=y1+y2;
 
subplot(4,1,1)
plot(t,y)
title('for y')
xlabel('t')
ylabel('y')
grid on
gtext('1841014009')
subplot(4,1,2)
plot(t,y1)
title('for y1')
xlabel('t')
ylabel('y1')
grid on
gtext('1841014009')
 
subplot(4,1,3)
plot(t,y2)
title('for y2')
xlabel('t')
ylabel('y2')
grid on
gtext('1841014009')
  
subplot(4,1,4)
plot(t,y3)
title('for y3')
xlabel('t')
ylabel('y3')
grid on
gtext('1841014009')
 
if round(y)==round(y3)
    disp('system is linear');
    text(-2,-0.5, ('System Is Linear'));
    
else disp('system is non linear');
    text(-2,-0.5, ('System Is Non-Linear'));
end
% FOR STABILITY TEST
clc
clear all
close all
t=0:0.01:10
l=length(t)
for i=1:l
    if t(i)>=0
        x(i)=1;
        
    else x(i)=0;
    end
end
 
y=exp(-2*t).*x
c=0
for i=1:l-1
    if (y(i)>y(i+1))
        c=c+1;
    end
end
 
subplot(2,1,1)
plot(t,x)
title('for x')
xlabel('t')
ylabel('x')
grid on
gtext('1841014009')
subplot(2,1,2)
plot(t,y)
title('for y')
xlabel('t')
ylabel('y')
grid on
gtext('1841014009')
if(c~=0)
    disp('system is stable');
    text(2,0.5, ('System Is Stable'));
else 
    disp('system is unstable');
    text(2,0.5, ('System Is Untable'));
end

MATLAB: What am i doing wrong in this code

Looks like you have a piecewise function at the very beginning. If you have Symbolic Toolbox, it will be really easy for you to implement it and plot whatever you want. Try this:

syms t
x(t)=piecewise(t>=0 & t<=1,1,t>1,-t+2);
figure(1)
a=0;b=1;
t=0-a:0.01:2-a;
plot(b^-1*t,x(b*t));grid on;title('x(t)')
figure(2)
a=1;b=1;
t=0-a:0.01:2-a;
plot(b^-1*t,x(b*t+a));grid on;title('x(t+1)')
figure(3)
a=1;b=1;
t=0-a:0.01:2-a;
plot(sort(-(b^-1*t),'ascend'),x(-(b*t)+a));grid on;title('x(-t+1)')
figure(4)
a=0;b=1.5;
t=0-a:0.001:2-a;
plot(t,x(b*t+a));grid on;title('x((3/2)*t)')
figure(5)
a=1;b=1.5;
t=0-a:0.01:2-a;
plot(t,x(b*t+a));grid on;title('x((3/2)*t+1)')

Best Answer

Related Solutions

MATLAB: Verification of system characteristics

MATLAB: What am i doing wrong in this code

Related Question