MATLAB: How to divide image into 5*5 blocks

blockprocImage Processing ToolboxMATLABsize;

hello, i have a binarized image of fingerprint that i want to divide into 5*5 blocks and then count the number of zeros " black points " in each block

thanks in advance

Best Answer

blockproc(YourImage, [5 5], @(block) nnz(~block.data), 'trimborder', false)

Related Solutions

MATLAB: Converting JPG images into a cell arrays

sz = size(img);
RB = 28; CB = 28;
NRB = floor(sz(1)/RB);
LOR = sz(1) - NRB*RB;
NCB = floor(sz(2)/CB);
LOC = sz(2) - NCB*CB;
if LOR ~= 0
  rbs = [RB * ones(1,NRB), LOR];
else
    rbs = RB * ones(1,NRC);
end
if LOC ~= 0
    cbs = [CB * ones(1,NCB), LOC];
else
    cbs = CB * ones(1,NCB);
end
tiles = mat2cell(img, rbs, cbs, size(img,3));

MATLAB: Divide image into block of size 1*2

image_blocks = num2cell(TheImage);

Now image_blocks{J,K} will be the 1 x 1 block corresponding to the pixel at TheImage{J,K}

I cannot think of any advantage of dividing into 1 x 1 blocks, unless perhaps it is for convenience in holding the bit equivalent as a unit ? But if that is the situation then

bit_cells = arrayfun(@(V) dec2bin(V,8), TheImage, 'Uniform', 0);

Best Answer

Related Solutions

MATLAB: Converting JPG images into a cell arrays

MATLAB: Divide image into block of size 1*2

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