MATLAB: How to divide an image into 3*3 grids

image processing 3*3 grids

I have a set of leaf images of different sizes..I want to divide an image into 3*3 grids and then applying processing on that 3*3 grids individually..Can anyone please tell how to divide an image into 3*3 grids?

Best Answer

Have a look at blockproc

result = blockproc(img, [3 3], @somefun);

Related Solutions

MATLAB: Can anybody please help me to do the following

You can use mat2cell to divide a matrix into submatrices:

img = uint8(randi([0 255], 206, 100, 3)); %for example

n = 10; %for example
rowdist = n * ones(1, ceil(size(img, 1) /  n));
rowdist(end) = size(img, 1) - sum(rowdist(1:end-1)); %in case n is not a divisor of the image height
coldist = n * ones(1, ceil(size(img, 2) /  n));
coldist(end) = size(img, 2) - sum(coldist(1:end-1)); %in case n is not a divisor of the image width
subimgs = mat2cell(rowdist, coldist, size(img, 3))

To convert the cell array of matrices to a cell array of vectors:

subimgv = cellfun(@(m) m(:), subimgs, 'UniformOutput', false)

MATLAB: How to divide a bmp image into blocks

Assuming your image size is a multiple of 8:

img = imread('C:\somewhere\someimage.bmp');
numblockheight = size(img, 1) / 8;
numblockwidth = size(img, 2) / 8;
assert(all(mod([numblockwidth, numblockheight], 1) == 0), 'Image size is not a multiple of 8')
imageblocks = mat2cell(img, ones(1, numblockheight) * 8, ones(1, numblockwidth) * 8, size(img, 3))

And to save all these:

destinationfolder = 'C:\somewhere';
for col = 1:size(imageblocks, 2)
   for row = 1:size(imageblocks, 1)
      imwrite(imageblocks{row, col}, fullfile(destinationfolder, sprintf('block%03d_%03d.bmp', row, col)));
   end
end

Best Answer

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MATLAB: Can anybody please help me to do the following

MATLAB: How to divide a bmp image into blocks

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