I would like to find all models contained in a simulink model programmatically ?
Is there a way to do that for instance with the get_param(model_name, argument) function ?
There is a 'Parent' argument but no 'Children' argument for this function
MATLAB: How to discover all submodels within a simulink model programmatically
get_parammodel hierarchysimulink
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Hi Mark,
the only way I could think of:
myModelName = get_param(bdroot(gcb), 'Name');% find all model reference blocks that contain "me"
blocks = find_system('BlockType', 'ModelReference', ... 'ModelName', myModelName);models = bdroot(blocks);Does this help?
Titus
Try this:
% Create sample data.
numCircles = 10;xy = rand(numCircles, 2);radii = 0.1 * rand(numCircles, 1) + 0.1;viscircles(xy, radii);% Label them so we know what circle is what.
for k = 1 : numCircles text(xy(k, 1), xy(k, 2), num2str(k));endaxis square;% See if any intersect
for k = 1 : numCircles % Compute the distance between centers.
distances = sqrt((xy(k, 1) - xy(:, 1)).^2 + (xy(k, 2) - xy(:, 2)) .^2); sumOfRadii = radii(k) + radii(:); intersectingIndexes = distances < sumOfRadii; % Don't compare circle to itself. Of course that one intersects!
intersectingIndexes(k) = false; % Convert to linear indexes
intersectingIndexes = find(intersectingIndexes); for k2 = 1 : length(intersectingIndexes) fprintf('Circle %d intersects with circle #%d.\n', k, intersectingIndexes(k2)); endend
You see
Circle 1 intersects with circle #2.
Circle 1 intersects with circle #5.
Circle 1 intersects with circle #7.
Circle 2 intersects with circle #1.
Circle 2 intersects with circle #5.
Circle 3 intersects with circle #7.
Circle 3 intersects with circle #9.
Circle 5 intersects with circle #1.
Circle 5 intersects with circle #2.
Circle 6 intersects with circle #10.
Circle 7 intersects with circle #1.
Circle 7 intersects with circle #3.
Circle 8 intersects with circle #9.
Circle 9 intersects with circle #3.
Circle 9 intersects with circle #8.
Circle 10 intersects with circle #6.
and it's trivial to find out if one circle is completely contained within another. See if you can do it.
Best Answer