MATLAB: How to delete leading zeros in a row vector in MATLAB

I have created a function which multiplies two factorials together in MATLAB and the final result is:

0000000000000000000000000000000000000000

0000000000000005127485891768928006848657

3067757467756330382900027197934928341442

4644048874750576347830749966301579885959

6864463688769208320000000000000000000000

I need to delete the leading zeros, without deleting the trailing zeros. Anyone know how to do this?

Would help a lot, thanks

Best Answer

If it's a vector of chars, this should do:

 data = regexprep(data,'^0*','')

Related Solutions

MATLAB: How to make a vector of zeros.

n = number of zeros
v = zeros(1,n);

MATLAB: Time-optimization? Digital image processing

The vectorized method of finding the first non-zero pixel for each column is:

leading_zero_count = sum( cumprod( ~D ) );

This will do the operation for all columns for all images simultaneously. The output will be 1 x number_of_columns x number_of_images

This is the count of the number of leading zeros, which is not exactly the same as the location of the first non-zero pixel. For any column that has a non-zero pixel, the leading zero count will be 1 less than the position of the first non-zero pixel. For any column that does not have any non-zero pixels, the leading zero count will be the same as the number of rows, which is a non-empty value, where-as the result of find() for such a case would be [] (the empty vector). A leading zero count can be easier to work with:

D(leading_zero_count(1,J,K)+1:end, J, K)

is easy to code without having to test for the [] that find() can return.

Best Answer

Related Solutions

MATLAB: How to make a vector of zeros.

MATLAB: Time-optimization? Digital image processing

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