MATLAB: How to define the time steps of an x-y plot

MATLABtime steps

Hi! I'm trying to make a script, which plots this equations.
https://www.wolframalpha.com/input/?i=plot+x%3D100*t%2B1.2*sin(2*pi*200*t)+and+y%3D0.6*sin(2*pi*200*t%2Bpi%2F2)+for+t+from+0+to+0.4
my code so far:
clc;clear;
t=0 % Time
tend=0.40 % end time
dt=0.01; % Time step
f=200; % Frequency in Hz
vs=100; %Velocity in x in mm/s
A1=1.2; %Amplitude in y-direction
A2=0.6; %Amplitude in x-dirction
for t=0:dt:tend;
    X=vs*t+A1*sin(2*pi*f*t);
    Y=A2*sin(2*pi*f*t+pi/2);
    plot (X, Y,'-b')
end
How can I define my time steps so that I get the same plot like like the one from the link? There is sth wrong with my time step.
Thnaks in advance

Best Answer

Hello,
To get the same figure, you should refine the time step and then you should store value of X and Y with respect to t before you plot them. For example, some lines below will give the same figure 
clc;
clear;
close all
tend=0.40; % end time
dt=0.0001; % Time step
f=200; % Frequency in Hz
vs=100; %Velocity in x in mm/s
A1=1.2; %Amplitude in y-direction
A2=0.6; %Amplitude in x-dirction
t = 0:dt:tend;
X=vs*t+A1*sin(2*pi*f*t);
Y=A2*sin(2*pi*f*t+pi/2);
plot(X,Y,'-b')
xlabel('x')
ylabel('y')
% for t=0:dt:tend
%     X(i)=vs*t+A1*sin(2*pi*f*t);
%     Y(i)=A2*sin(2*pi*f*t+pi/2);
%     plot (X, Y,'-b')
%     hold on
% end
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