I'm going to guess you mean this instead, and wanted to create Y from X accordingly.
X=[1 1 0 1 1 1 0 0 0 1 1 1 1 1 0 0 1 0 0 0 1 1 1 1 0];
c=[2 3 5 1 4];
h=mean(c);
for k=1:numel(c)
if c(k)>h
c(k)=c(k);
elseif c(k)<=h
c(k)=0;
end
end
This can be solved with the code below.
X=[1 1 0 1 1 1 0 0 0 1 1 1 1 1 0 0 1 0 0 0 1 1 1 1 0];
encoded=bwlabel(X);
c=histc(encoded,1:max(encoded));
ind=find(c<=mean(c));
Y=X;
Y(ismember(encoded,ind))=0;
Y_check=[0 0 0 0 0 0 0 0 0 1 1 1 1 1 0 0 0 0 0 0 1 1 1 1 0];
isequal(Y,Y_check)
Best Answer