MATLAB: How to create random binary matrix with specified number of ones in each row and column

binary matrixmatrixsparse

Number of raws = M, number of columns = N, number of one's in each row = Nrow, number of one's in each column = Ncolumn.

Best Answer

See https://www.mathworks.com/matlabcentral/answers/439541-how-to-create-a-random-binary-matrix-with-equal-number-of-ones-in-each-column-and-equal-number-of-1#answer_356191 for practical code (but which I do not promise will always work.)

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MATLAB: How to place a cell array in another cell array using ‘find’

If I understood correctly:

Ax = randi([0 1], 4, 960);  %Demo data. No way I'm reformating your example to make it valid matlab syntax. 
[row, col] = find(A);
blockidx = discretize(col, 1:60:size(A, 2));
Bx = accumarray([row, blockidx], col, [], @(c) {sort(c).'})

Note: I'm not working on the whole cell array here, just one of these 4x960 matrix as I've not understood what that had to do with the question. Possibly, you just want to above in a loop (or cellfun) operating over each element of the cell array.

MATLAB: Creating a large matrix with a pattern

Hi bus14,

Try this:

m=zeros(804,200);
m([1,2,4],:)=1;
m2=reshape(m,800,[]);
m2(:,201)=[];

Best Answer

Related Solutions

MATLAB: How to place a cell array in another cell array using ‘find’

MATLAB: Creating a large matrix with a pattern

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