MATLAB: How to create an array of 100 elements

arrayelements

How can I create an array of 100 elements with n-th element valued as 1 / √(2n^2)

Best Answer

n=1:100
sequence =  1 ./ sqrt(2*n.^2)

syms n
s=1:99
sequence =  1 ./ sqrt(2*n.^2)
array =[ s sequence ]
array = subs(array,n,3)

Related Solutions

MATLAB: Matrix size is A(100*100). Weighted average of the 4 elements.

In the original question and the image you mentiones 2x2 submatrices. In the commend you talk of 4x4 submatrices. This is not clear in this sentence also:

These 4x4 matrices are unique; i.e., I have to take the first two elements of the first row and same elements of the second row and average it.

Here I used n=4, but perhaps you want n=2:

n = 4;
X = rand(100, 100);
Y = reshape(X, [n, 100/n, n, 100/n]);
Y = permute(Y, [2, 4, 1, 3]);         % Move dims of length n together
Y = reshape(Y, [100/n, 100/n, n*n]);  % Combine to subvectors of length n*n
Result = mean(Y, 3);                  % Mean over 3rd dimension

MATLAB: How to implement this formula in MatLab

directly:

n=100;
x=rand(1,n);
s=std(x)

or with a loop:

n=100;
x=rand(1,n);
xmean=mean(x);
sumt=0;
for i=1:n
    sumt=sumt+(x(i)-xmean)^2;
end
s=sqrt(sumt/(n-1))

Best Answer

Related Solutions

MATLAB: Matrix size is A(100*100). Weighted average of the 4 elements.

MATLAB: How to implement this formula in MatLab

Related Question