MATLAB: How to count the total number of occurrences of each digit avoiding the first elements of each cell

cell arrays

Suppose I have a cell array
C = {[1; 4; 7]; [2; 5; 8; 9]; [3; 4]};
c{:}
ans = 
1
4
7
ans =
2
5
8
9
ans=
3
4
   % where any digit won't repeat in the individual cell.
   % There are 4 stages in this cell array. 
   % first stage elements are 1, 2, 3
   % second stage elements are 4, 5, 4
   % third stage elements are 7,8
   % fourth stage elements are 9
I need to count the total number of occurrences of each digit except stage 1 that means by avoiding the first elements of each cell. Expected output:
Digit | Number of occurrences
  4        2
  5        1
  7        1
  8        1
  9        1

Best Answer

You could do the following if you don't mind using some for loops
 % example data  
C = {[1; 4; 7]; [2; 5; 8; 9]; [3; 4]};
 % get the highest digit to make an array in which you store your count  
highestDigit = max(cell2mat(C));
countArray = zeros(2, highestDigit);
 % replace the second row with the digits
countArray(2,:) = 1:highestDigit;
 % then loop over the cell array
for ii = 1:numel(C)
  digits = C{ii}(2:end); % filter out the first digit
  for jj=1:numel(digits)
     countArray(1,digits(jj)) = countArray(1,digits(jj)) + 1; % add one every time it occurs
  end
end
% remove the zeros
maskZeros = countArray(1,:)~=0;
countArray = countArray(:,maskZeros);
% print the result
fprintf('Digit  |  Number of occurrenced \n')
for ii = 1:length(countArray)
 fprintf('%d             %d \n',countArray(2, ii), countArray(1,ii)); 
end
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