MATLAB: How to count consuctive 0’s inbetween values of 1

Question

I have really long code that does what I want, but I wanted to try to find a faster code to do this, for loop is taking forever. for example I have a vector of:

count = [0; 1; 0; 0; 0; 1; 0; 1; 1; 1; 0; 0; 0; 1; 0; 1; 1; 0; 0]

What I would like for an answer is the consecutive 0's between the ones… so,

ans =

     1
     3
     1
     0
     0
     3
     1
     0
     2

Here is what I have to do it, (count coming in is the 1 and 0 vector list), the output is "store":

for m = 1:size(count,1)

    store = 0;
    countlast = 0;
    j = 0;
    if (sum(count)>=1)
        for n = 1:size(count,1)
            if count(n) == 0
                countlast = countlast + 1;
            else
                j = j + 1;
                store(j) = countlast;
                countlast = 0;
            end
        end
        j = j + 1;
        store(j) = countlast;
    end

end

store'

If there is a faster way of doing this Please help me out! Thanks, Chris

Answer 1

This is a fun one.

Try

count = reshape(count,1,[]); % make it a row vector
store = [nnz(cumsum(count)==0),...
         diff(find(count))-1,...
         nnz(cumsum(count)==max(cumsum(count)))-1]