MATLAB: How to compute a column with seasons (1 to 4) based upon a date

columnseason

I want to compute a column with seasons (1 to 4) based upon a date?

For instance: 1-12-2018, month=1, so that means season 2?

Any tips for my problem?

Thomas

Best Answer

datevec is useful in your case. You may proceed something like this:

dt = datevec('1-12-2018') ;
month = dt(:,1) ;

month gives you all the months..now use logical indexing..

seasons = zeros(size(month)) ;
seasons(month==1) = 1 ;

Related Solutions

MATLAB: Write a script that will prompt the user for the month of interest.

Don't have the function keyword since it's supposed to be a script. You need to do something like

      theMonth = input('Enter a month: ','s');
      switch lower(theMonth)
          case {'dec', 'jan', 'feb'}
              season = 'Winter';
          case {'mar', 'apr', 'may'}
              season = 'Spring';
          case {'jun', 'jul', 'aug'}
              season = 'Summer';
          case {'Sep', 'oct', 'nov'}
              season = 'Autumn';
          otherwise
              season = 'Unknown';
      end
      fprintf('%s is a month in %s.\n', theMonth, season)

MATLAB: Select season from monthly series

Assuming that you mean that the values of the third column go from 0 to 756, that is it is the number of months elapsed since January 1951, I would convert that 3rd column into a calendarDuration, add that to your epoch to produce a datetime array, then simply filter on the month:

 A = [rand(756, 2), (0:756)']; %demo data
 caldur = calendarDuration(0, A(:, 3), 0); 
 actualdate = datetime(1951, 1, 1) + caldur; %convert into datetime from 1st January 1951
 monthnumber = actualdate.Month;
 filteredA = A(monthnumber >= 6 & monthnumber <= 9, :) %only keep June (6th month) to September (9th month)

Best Answer

Related Solutions

MATLAB: Write a script that will prompt the user for the month of interest.

MATLAB: Select season from monthly series

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