MATLAB: How to change this matrix in this manner

matrix

how to manipulate this matrix without for loop:

A=[a1,b1,c1,d1.......;a2,b2,c2,d2..........;a3,b3,c3,d3.......;a4,b4,c4,d4....;..]
how to get this:
H=[a1,b1,a2,b2,a3,b3,......;c1,d1,c2,d2,c3,d3,........]

thank you

Best Answer

H = [reshape(reshape(A(:,1:2),[],2)',[],1);reshape(reshape(A(:,3:4),[],2)',[],1)];

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MATLAB: Fprintf 13 values in a 5×4 matrix without zeros.

The following might help (not tested):

 nCol = 4 ;
 Dt   = D.' ;
 nDt  = numel(Dt) ;
 for ii = 1 : nDt
    if Dt(ii) ~= 0,  fprintf(fid, '%10i', Dt(ii)) ;  end
    if ii < nDt,  fprintf(fid, ',') ;  end
    if ~mod(ii, nCol),  fprintf(fid, '\n') ;  end
 end

The initial transpose allows us to index Dt linearly for reading D along rows.

MATLAB: Grid structure in wsn..

One_grid_info = struct('UID', -inf, 'lat', -inf, 'long', -inf, 'Energy', 10000, 'InputBuffer', [], 'OutputBuffer', []);
nrows = 17;
ncols = 12;
wsn_grid(nrows, ncols) = One_grid_info;
for row = 2:nrows - 1
    row_above = row - 1;
    row_below = row + 1;
    for cols = 2:ncols - 1
        col_left = cols - 1;
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Best Answer

Related Solutions

MATLAB: Fprintf 13 values in a 5×4 matrix without zeros.

MATLAB: Grid structure in wsn..

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