Hello , I have a similar kind of problem like y = [1 2 1 1 1] and z = [1 2 -3 4 -5] and v(z) = z^3 now i have to calculate h(z) = v(z).*y but the condition is when i calculate h only negative values in the anonymous fn of v(z) must become zero. can someone tell me how?
z = [1 2 -3 4 -5];y = [1 2 1 1 1];v =@ (z) z.^3;h = v(z).*y
I am getting h = [1 16 -27 64 -125] but i need h = [1 16 0 64 0]
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