MATLAB: How to chang matrix size 81x81x30 to 81x81x32 by add row

chang size matrix

Hi all….

I have matrix size 81 x 81 x30 ( 3D )

i want to be 81 x 81 x 32

chang size matrix by add 2 row (zero number)

here the example in this file ( daily_avg_u.mat )

Best Answer

daily_avg_u(:,:,end + (1:2)) = zeros([size(daily_avg_u(:,:,1)),2]);

Related Solutions

MATLAB: Add zeros to matrices same as length of another matrix

can I add zeros to the bold 360x3 matrix to make it 369x3 in one go?

You say you want to add 9 rows but you are trying to add columns with your code. Probably something like,

 bold1=[bold1; zeros(size(X(:,1),1)-size(bold1,1),3)];

...Dimensions of matrices being concatenated are not consistent...

This simply means what it says. For example,

   >> A = [1 2;3 4]
  A =
       1     2
       3     4
  >> B = [5 6 7; 8 9 0]
  B =
       5     6     7
       8     9     0
  >> C = [A; B]
  Error using vertcat
  Dimensions of matrices being concatenated are not consistent.

You cannot stack them up and down (vertical cancatenation, hence vertcat) because they have different number of columns (hence not consistent!).

But if you want to stack them side by side (horizontal)

>> C = [A B]
C =
     1     2     5     6     7
     3     4     8     9     0

Now you can, because they have same number of rows. Simple!

MATLAB: How to do a double integral on a function with 3 variables, so the answer is dependent on the 3 variable

Not sure what your problem with INTEGRAL2 was, but you're using matrix multiplication in your definition of FUN, which probably isn't right--I doubt you want to multiply a matrix of WBLPDF values by a matrix of MVNPDF values, and you're stacking u and k as different rows when you input to MVNPDF when I think what you should be doing is passing them as different columns. Assuming you meant to integrate over u and k first and to have a function of x coming out, this might be the sort of thing you want:

C = [23.875 15.75281; 15.75281 93.9842];
mu_U = 1788.2058;
mu_K = 70.8489;
sigma_U = sqrt(C(1,1));
sigma_k = sqrt(C(2,2));
ubot = mu_U-4*sigma_U;
utop = mu_U+4*sigma_U;
kbot = mu_K-4*sigma_k;
ktop = mu_K+4*sigma_k;
mu = [mu_U;mu_K];
fun = @(x,u,k) wblpdf(x,u,k).*reshape(mvnpdf([u(:),k(:)],mu(:).',C),size(u));
qfun_scalar = @(x)integral2(@(u,k)fun(x,u,k),ubot,utop,kbot,ktop,'AbsTol',1e-10,'RelTol',1e-6);
qfun = @(x)arrayfun(qfun_scalar,x);

I just threw the tolerances in there in case you wanted to play with them.

Now you can use qfun to evaluate for x values (scalar or arrays), or you can integrate over ranges of x, or whatever.

>> qfun(1750)
ans =
   0.006956904221022
>> integral(qfun,1600,1800)
ans =
   0.789977339847138

Best Answer

Related Solutions

MATLAB: Add zeros to matrices same as length of another matrix

MATLAB: How to do a double integral on a function with 3 variables, so the answer is dependent on the 3 variable

Related Question