if true A = [10 2 -1;-3 -6 2;1 1 5];b = [27;-61.5;-21.5];X = zeros(length(b),1);error = ones(length(b), 1)*100;iteration = 0;fprintf('Iteration\t x1\t\t x2\t\t x3\t\tError1\t Error2\t\tError3\t\tMax. error\n') while max(error) > 5 iteration = iteration + 1; Z = X; for i = 1:length(b) j = 1:length(b); Xnow = X; Xnow(i) = 0; X(i) = (b(i) - sum(A(i,j)*Xnow))/A(i,i); end error = abs((X - Z)./X)*100; fprintf(' %4.0f\t\t%4.5f\t\t%4.5f\t\t%8.5f\t%4.2f%%\t %4.2f%%\t\t%4.2f%%\t %4.2f%%\n', iteration, X(1), X(2), X(3), error(1), error(2), error(3), max(error))endend
The code produces the table attached.
How can I straighten the values under Max. error and Error3?
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