MATLAB: How to calculate ratio of elements of a column

ratio of elements of the same column

I want to calculate the ratio of elements of each column. For ex: my column has data A = [ 1;2;3;4;5;6;7;8;9;10] and I want to calculate the ratio of elements for which the numerator and denominator are the elements of the consecutive rows leaving the first row. B(1) = 2/1, B(2) = 3/2, B(3) = 4/3, and so on.. finally B = [2; 3/2; 4/3; 5/4;…]

Best Answer

>> B = A(2:end)./A(1:end-1)
B =
            2
          1.5
       1.3333
         1.25
          1.2
       1.1667
       1.1429
        1.125
       1.1111

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MATLAB: How to check if two elements are in a row of a matrix

Here is one clumsy way:

A=[1 2;
   4 5;
   6 9];
B=[1 3 5 6;
   1 2 4 7;
   5 6 4 8;
   1 2 3 4];
rowCountA = size(A,1);
rowCountB = size(B,1);
this_row_of_A_is_in_B = false(rowCountA,1);
for nb = 1:rowCountB
    this_row_of_A_is_in_B = this_row_of_A_is_in_B | all(ismember(A,B(nb,:)),2);
end
rows_of_A_that_are_not_in_B = A(not(this_row_of_A_is_in_B),:)

MATLAB: How to create a linspace with a condition

Hi,

if you know the maximum allowed spacing you can use:

function result = mySpacing(StartValue,EndValue,maxSpaceValue)
result = linspace(StartValue,EndValue,ceil((EndValue-StartValue)/maxSpaceValue+1)); 
end

This will ensure that the spacing is always smaller or equal to the given argument:

result1 = mySpacing(1,2,0.12)
result1 =
  Columns 1 through 9
    1.0000    1.1111    1.2222    1.3333    1.4444    1.5556    1.6667    1.7778    1.8889
  Column 10
    2.0000
    
    
result2 = mySpacing(0,2,0.15)
result2 =
  Columns 1 through 9
         0    0.1429    0.2857    0.4286    0.5714    0.7143    0.8571    1.0000    1.1429
  Columns 10 through 15
    1.2857    1.4286    1.5714    1.7143    1.8571    2.0000
    
result3 = mySpacing(0,2,0.5)
result3 =
         0    0.5000    1.0000    1.5000    2.0000

Best regards

Stephan

Best Answer

Related Solutions

MATLAB: How to check if two elements are in a row of a matrix

MATLAB: How to create a linspace with a condition

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