Hi! I have a cell array with this values
a={'2' '3' '4' '5'; '2' '2' '3' '1'; '2' '2' '2' '1';'1' '2' '3' '3'; '1' '2' '3' '4'};a = '2' '3' '4' '5' '2' '2' '3' '1' '2' '2' '2' '1' '1' '2' '3' '3' '1' '2' '3' '4'
and I want to count the number of consecutive values in the colums I consider the first two columns and I find the couples:
('2' '3'), ('2' '2') ('1' '2')
I want to find the number of times that this couples are presents in the first two colums
('2' '3') --> 1('2' '2') --> 2('1' '2') --> 2
After I consider the triple
('2' '3' '4'), ('2' '2' '3'), ('2' '2' '2'), ('1' '2' '3')
I want to find the number of times that this couples are presents in the first three columns:
('2' '3' '4')--> 1('2' '2' '3')--> 1('2' '2' '2')--> 1('1' '2' '3')--> 2
After I consider the quadruple
('2' '3' '4' '5'), ('2' '2' '3' '1'), ('2' '2' '2' '1'), ('1' '2' '3' '3') ('1' '2' '3' '4')
I want to find the number of times that this couples are presents in the four columns:
('2' '3' '4' '5')--> 1 ('2' '2' '3' '1')--> 1 ('2' '2' '2' '1')--> 1 ('1' '2' '3' '3')--> 1 ('1' '2' '3' '4')--> 1
Can you help me?
Best Answer