MATLAB: How to access specific integer values from a String and Convert into Integers

castconvertdatatypesMATLABstr2numstringstypecast

I have a MATLAB String "2018-04-24 04:30:00". I would like to access two specific values and save them as integers, i.e.

year = 2018

month = 04

I tried using str2num but it truncates the entire string because I can't apply it directly to the original string in that sense. My ultimate aim is to access the integer values of 2018 and 04 from this very string and save these into 2 seperate integer type variables – year and month. Any help in this regard from the MATLAB Community would be highly appreciated.

Thanks!

Best Answer

To get numerical results (integer values) use ymd function:

A = "2018-04-24 04:30:00"
[Year, Month, Day] = ymd(datetime(A))

gives:

A = 
    "2018-04-24 04:30:00"
Year =
        2018
Month =
     4
Day =
    24

For only month and day use:

[~, Month, Day] = ymd(datetime(A))

The answer above returns the result as datatype datetime.

Best regards

Stephan

Related Solutions

MATLAB: Hi, i have two dates like 2013_12_28 and 2014_01_06, and i want to calculate the mean date (2014_01_01) which would be in the form of 2014.0014

md = mean(datenum({'2013_12_28', '2014_01_06'}, 'YYYY_mm_dd'));
dv = datevec(md);
days_into_year = md - datenum([dv(1),1,1]);

But once you have days_into_year you have to convert that into a year fraction, which requires careful definition of how long a "year" is. Is a "year" 365 days, always? Is a "year" 365.2421875 days? Is a "year" 365 days for non-leap years but 366 days for leap-years? If so then should it be 365 days for dates in the year before the leap day but 366 for dates on or after the leap day?

Converting to a specific date is much easier, and getting the result in terms of days is easy, but fraction of a year needs clarification.

MATLAB: Timezone to UTC: How to add duration vector to datetime vector

Frank, what's up is Daylight Saving Time, which occurred on March 8th this year. I'm guessing you knew that, but got mixed up in the time arithmetic. Here's what's going on. You have this:

>> time = ['2015/03/08 00:00';'2015/03/08 01:00';'2015/03/08 03:00';'2015/03/08 04:00'];
>> Time = datenum(time,'yyyy/mm/dd HH:MM')
Time =
                    736031
          736031.041666667
                736031.125
          736031.166666667

datenums don't know anything about time zones or DST. Those times mean whatever you want them to mean. Since you then do this ...

>> date = datetime(Time,'ConvertFrom','datenum','Timezone','America/Montreal')
date = 
   08-Mar-2015 00:00:00
   08-Mar-2015 01:00:00
   08-Mar-2015 03:00:00
   08-Mar-2015 04:00:00

... I assume you mean that those datenums are to be interpreted as times in the America/Montreal time zone. But what you've left out is this:

>> date.Format = [date.Format ' z']
date = 
   08-Mar-2015 00:00:00 UTC-5
   08-Mar-2015 01:00:00 UTC-5
   08-Mar-2015 03:00:00 UTC-4
   08-Mar-2015 04:00:00 UTC-4

The second and third times are only an hour apart. Then this ...

>> [UTC_Offset,dst] = tzoffset(date);
>> Date = date - UTC_Offset
Date = 
   08-Mar-2015 06:00:00 UTC-4
   08-Mar-2015 07:00:00 UTC-4
   08-Mar-2015 07:00:00 UTC-4
   08-Mar-2015 08:00:00 UTC-4

... adds 5 hours to the first and second times, but adds only 4 hours to the third and fourth times. But you're doing the addition in the America/Montreal time zone. Adding 5 hours to the first two puts them after the DST shift @2am, which makes them look like you added 6 hours. In other words, your array is not UTC, it's shifted America/Montreal. The easiest thing to do to get UTC times is this:

>> date.TimeZone = 'UTC'
date = 
   08-Mar-2015 05:00:00 UTC
   08-Mar-2015 06:00:00 UTC
   08-Mar-2015 07:00:00 UTC
   08-Mar-2015 08:00:00 UTC

Hope this helps.

Best Answer

Related Solutions

MATLAB: Hi, i have two dates like 2013_12_28 and 2014_01_06, and i want to calculate the mean date (2014_01_01) which would be in the form of 2014.0014

MATLAB: Timezone to UTC: How to add duration vector to datetime vector

Related Question