MATLAB: How the function typecast works when convert double to uint8

format conversiontypecast

I test the function typecast as follows:
z=double(1);
z1=typecast(z,'uint8');
and the results shows the
z1 = 0 0 0 0 0 0 240 63
As to my knowledge, each element in z1 should represent one 8-bit unsigned number. But the sum is not equal to 1.
Does anyone know how the function works and what's the meaning in vector z1?

Best Answer

Look at the difference between CAST and TYPECAST, and you will understand what happens in your example.
PS: if you want to understand where these 240(F0) and 63(3F) come from, have a look a this wiki.