Let a
a = 1 4 3 5 4 7 6 8
be integer intervals
[1 2 3 4] [3 4 5] [4 5 6 7] [6 7 8]
I'm looking for an output b to count the number of times each element appears. It is clear that 1 appears one time, 2 appears one time, 3 appears twice, and so on…
So the output b would list the element and how many times it appears:
b = 1 1 2 1 3 2 4 3 5 2 6 2 7 2 8 1
The challenge is, a is an extremely large nx2 array, so using find even with parallel looping is inefficient. Is there a fast way to yield b given a? If it helps, we can be sure that the elements down the left-hand column of a are sorted, but not necessarily so for the right-hand column. Thanks in advance!
Best Answer