MATLAB: How made the code as easy

matlab for loop function only

P=[1 32 3 78 5 6 7 8 9 10] ;P is my original array which has the size is 1*10; I have Q=[2 4 7];I want delete in Q array value in P array; My expect output is P=[ 1 3 5 6 8 9 10] by using for loop only because of the size of Q array may be change ;P(:,[Q(1) Q(2) Q(3)])=[] this command use only the size of Q array is 1*3 .So I need for loop logic which is common of any array size.

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P(Q)=[] %edited after Jan's comment

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MATLAB: Inner matrix dimensions must agree

fkj= sum(.5*((p.^2-q.^2).^2)./((p.*q).^1.5));

Note that .^ .* and ./ operators are used for element-wise operation (see also Stephen's comment).

Note also that dot can give apparently unexpected results for complex inputs (see dot help)

MATLAB: How to automate ARIMA model ‘order’ selection based on ACF and PACF plots

I am not sure that it is your answer or not. But I have used this function to find the best values for p and q for a given time series y

function ar=checkArima(y,pp,qq)
% pp is the maximum for p
% qq is the maximum for q
LOGL = zeros(pp+1,qq+1); %Initialize
PQ = zeros(pp+1,qq+1);
for p = 1:pp+1
    for q = 1:qq+1
        mod = arima(p-1,0,q-1)
        [fit,~,logL] = estimate(mod,y,'print',false);
        LOGL(p,q) = logL;
        PQ(p,q) = p+q;
     end
end
LOGL = reshape(LOGL,(pp+1)*(qq+1),1);
PQ = reshape(PQ,(pp+1)*(qq+1),1);
[~,bic] = aicbic(LOGL,PQ+1,100);
ar=reshape(bic,pp+1,qq+1);
% the rows correspond to the AR degree (p) and the
% columns correspond to the MA degree (q). The smallest value is best

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Related Solutions

MATLAB: Inner matrix dimensions must agree

MATLAB: How to automate ARIMA model ‘order’ selection based on ACF and PACF plots

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