MATLAB: How I find rows with same elements but in flipped manner.

rowsunique

Hi, I have a matrix suppose A=[1 2;3 4;2 1; 5 3;4 3]; I need to detect row 1 and 3 as well as row 2 and 5 as unique row. my final matrix should be like A=[1 2;3 4;5 3];

Thank you in Advance

Best Answer

A  = [1 2;3 4;2 1; 5 3;4 3];
As = sort(A, 2);   % [EDITED], was: sortrows(A)
Au = unique(As, 'rows');

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MATLAB: Identifying the repeated rows in a matrix and comparing them to another matrix

Hello,

you can refer my answer as follows

clear
A= [4 4; 2 3; 4 2; 3 3; 2 3; 1 3; 3 3];
B=[1 1; 2 1; 3 1; 4 1; 1 2; 2 2; 3 2; 4 2; 1 3; 2 3; 3 3; 4 3; 1 4; 2 4; 3 4; 4 4];
n = size(A,1);
rowAinB = [];
for i = 1:n
    [LIA,LOCB] = ismember(A(i,:),B,'rows','legacy');
    if ~isempty(LOCB)
        rowAinB = [rowAinB i];
    end
end
repeatA = [];
C = unique(A,'rows','stable');
for i = 1:n
    [LIA,LOCB] = ismember(A(i,:),C,'rows','legacy');
    repeatA = [repeatA LOCB];
end
m = size(C,1);
coutrepeatA = zeros(m,1);
for i = 1:m
    idx = find(repeatA == repeatA(i));
    coutrepeatA(i) = length(idx)-1;
end

the unique of matrix A is C and number of repeated row of C is stored in vector "coutrepeatA". As you can see the results below

A =
     4     4
     2     3
     4     2
     3     3
     2     3
     1     3
     3     3
     
C =
     4     4
     2     3
     4     2
     3     3
     1     3
     
coutrepeatA =
     0
     1
     0
     1
     1

Best regards,

Trung

MATLAB: Remove cell array content matrix with condition: length of element in cell smaller than specific value

cell_A = {[1 1 1;2 2 2;3 3 3;4 4 4;5 5 5];[11 11 11];[0 0 0;1 1 1;2 2 2;3 3 3;4 4 4;5 5 5]};
cell_A(cellfun(@size,cell_A,repmat({1},size(cell_A))) < 2) = [];

Best Answer

Related Solutions

MATLAB: Identifying the repeated rows in a matrix and comparing them to another matrix

MATLAB: Remove cell array content matrix with condition: length of element in cell smaller than specific value

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