MATLAB: How i can… meshgrid in matlab

homeworkmeshgrid

how i can run this formula with this command: meshgrid

………………………..

formul: y=35.5+10.5×1+5.5×2+8x1x2

Best Answer

Try this:

xv = linspace(-1, 1, 20);
[x1,x2] = meshgrid(xv);
y = 35.5 + 10.5*x1 + 5.5*x2 + 8*x1.*x2;
figure
mesh(x1, x2, y)
grid on
set(gca, 'BoxStyle','full')
view(35, 35)
figure
contour(x1, x2, y)

Experiment to get the result you want.

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MATLAB: ‘Matrix dimensions must agree error’

You need a mesh to create contour plot

bbfun = @(x1,x2) (4-2.1.*x1.^2+x1.^4/3).*x1.^2 + x1.*x2 + (-4+4*x2.^2) .*x2.^2; 
x1 = -2:1/100:2;
x2 = -1.5:1/100:1.5;
[X1, X2] = meshgrid(x1, x2);
pltvar = bbfun(X1, X2);
contour(X1, X2, pltvar,20)

MATLAB: How to have ‘if statements’ when defining ‘constants’

I would create ‘SomeConstant’ as an anonymous function:

x = [0:100];
y = [0:100];
SomeConstant = @(y) [1*(y == 20) + 5*(y < 20) + 10*(y > 20)];
Test1 = @(x,y)(x+y)+SomeConstant(y);
Test2 = @(x,y)(x.^2+y)+SomeConstant(y);
[X1,Y1] = meshgrid(x,y);
Z1 = Test1(X1,Y1);
Z2 = Test2(X1,Y1);
s1 = surf(X1,Y1,Z1,'LineStyle','none');
hold on
s2 = surf(X1,Y1,Z2,'LineStyle','none');

You defined ‘SomeConstant’ to be 1, and then defined it as being 5 for y<20 and 10 for y>20. I created the anonymous function version with those conditions, adding the condition that it was 1 at y==20.

This works, but you have to determine if it produces the result you want.

Best Answer

Related Solutions

MATLAB: ‘Matrix dimensions must agree error’

MATLAB: How to have ‘if statements’ when defining ‘constants’

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