MATLAB: How can i decode(unpack) an array of bits with a constant value

decoding bitsunpacking bits

For example; I have an array; [0 0 0 1 1 1 0 0 0]. and a constant value L= 3 how can i get the output as; [0 1 0] ?

Not sure what the "rule" really is for getting the bits. Maybe one of these?

x = your vector
L = your number
result = x(1:L:end);

or maybe

result = any(reshape(x,L,[]));

or maybe

result = all(reshape(x,L,[]));

If not one of the above, then maybe you could give us more details on the "rules" for the unpacking.

How about this?

x = [1+j; -1-j; -1+j; 1-j];
result = [real(x)<0, imag(x)<0];

It turns a column vector of imaginary numbers into a two-column array with the results.

method one: median:

>> y = [0,1,0,0,1,1,0,0,1];
>> median(reshape(y,3,[]))
ans =
   0   1   0

method two: round:

>> round(mean(reshape(y,3,[])))
ans =
   0   1   0