MATLAB: How can i create in script y=cos(x), between (0,2*pi) linspace(0,1,n) and the angel is 10degrees using for (loop) and Disp and SprintF

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%sinefun3.m n=21; x=linspace(0,1,n); %x=2*pi*linspace(0,1,n); y=sin(2*pi*x); %y=sin(x); disp('hi ') disp(' k x(k) sin(x(k))') for k=1:n degrees = (k-1)*360/(n-1); disp(sprintf('%2.0f %3.0f %6.3f ',... k ,degrees,y(k))) end disp(' ') disp(sprintf('one Degree = %5.3e Radians ',... pi/180))

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MATLAB: Solving non linear equation using fsolve

You are not passing theta_n and other parameters to root2d(). One fix is to make root2d a Nested Function. Also, you must choose a different initial point. phi0 = [10,10] worked for me.

function solve_it()
    beta_a = 10;
    alpha_n = 10 ;
    eta= 18;
    i = 18;
    theta_i = 10;
    theta_n = 10 ;
    
    fun = @root2d;
    phi0 = [10,10];
    phi = fsolve(fun,phi0);
    phi_n = phi(1),
    phi_i = phi(2),
    function F = root2d(phi)
    F = zeros(2,1);
    F(1) = (pi*sin((pi*(phi(1) + theta_n))/180)*cos((pi*phi(2))/180)*(cos((pi*theta_n)/180) + tan((pi*i)/180)*tan((pi*theta_i)/180)))/(180*sin((pi*phi(1))/180)*(cos((pi*(phi(1) + theta_n))/180)*cos((phi(2)*pi)/180) + sin((phi(2)*pi)/180)*tan((theta_i*pi)/180))^2) - (pi*cos((pi*phi(1))/180)*(cos((pi*theta_n)/180) + tan((pi*i)/180)*tan((pi*theta_i)/180)))/(180*sin((phi(1)*pi)/180)^2*(cos((pi*(phi(1) + theta_n))/180)*cos((pi*phi(2))/180) + sin((pi*phi(2))/180)*tan((pi*theta_i)/180)));
    F(2) = ((cos((pi*theta_n)/180) + tan((pi*i)/180)*tan((pi*theta_i)/180))*((pi*cos((pi*(phi(1) + theta_n))/180)*sin((pi*phi(2))/180))/180 - (pi*cos((pi*phi(2))/180)*tan((pi*theta_i)/180))/180))/(sin((pi*phi(1))/180)*(cos((pi*(phi(1) + theta_n))/180)*cos((phi(2)*pi)/180) + sin((phi(2)*pi)/180)*tan((theta_i*pi)/180))^2);
    end
end

MATLAB: How can i plot radiation pattern in cartesian coordinate in matlab

Dear Naveedp, here is the code you can use for plotting:

theta = -90:90;
theta_rad = degtorad(theta);
r = 1;
elevation = 0;
[x,y,z] = sph2cart(theta_rad,elevation,r);
E_theta = 1j * 30 * exp(-1j * 2 * pi) * sin(5 * pi * sin(theta)) ./ (5 * pi * sin(theta));
E_phi = 1j * 30 * exp(-1j * 2 * pi) * cos(theta) .* sin(3 * pi * sin(theta)) ./ (3 * pi * sin(theta));
figure, subplot(2,1,1), plot3(x, y, abs(E_theta)), xlabel('x'), ylabel('y'), zlabel('z'), title('E(theta) amplitude')
        subplot(2,1,2), plot3(x, y, angle(E_theta)), xlabel('x'), ylabel('y'), zlabel('z'), title('E(theta) phase')
figure, subplot(2,1,1), plot3(x, y, abs(E_phi)), xlabel('x'), ylabel('y'), zlabel('z'), title('E(phi) amplitude')
        subplot(2,1,2), plot3(x, y, angle(E_phi)), xlabel('x'), ylabel('y'), zlabel('z'), title('E(phi) phase')

Since, I did't see use of angle phi so I assumed it to be 0 and assumed value of radius to be 1. I hope it will help you

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MATLAB: Solving non linear equation using fsolve

MATLAB: How can i plot radiation pattern in cartesian coordinate in matlab

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