MATLAB: HI, i want to plot x=sin(t*pi) fuction like this picture for t[0:1:24] and x will be 0 when t=17

forfunctionplotplotting

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figure out what azzi was doing in the math which would lead you to figure out what to change.

t=0:0.01:24
y=sin(t*pi).*(t<15) + 3*sin(t*pi).*(t>=15)
plot(t,y)

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MATLAB: Plotting a function with input and output

You need to change * to .* and change e to exp(), and you need to move the 5 exponent:

t=0:0.01*pi:20*pi; % Create t
[x, y] = bird(t); % Call the function.
function [x,y] = bird(t)
x = sin(t) .* (exp(cos(t)) - 2*cos(4*t)-sin(t/12).^5)
y = cos(t) .* (exp(cos(t)) - 2*cos(4*t)-sin(t/12).^5)
plot(x,y)
end

MATLAB: Is does the y axis of the graph have the same value all the way down

Are you sure that your formula is correct? You pass into cosine function not pi but pi^2 when you plot. You pass into variable t the vector x when you plot and this vector x is already the range of pi.

if you use instead

 y =@(t) 1.11*cos(100000*t) + 0.5*cos(98000*t) + 0.5*cos(102000*t); x = -2*pi:0.1:2*pi;
  plot(x,y(x))

you take

if the function is correct you have to take another interval

x = -pi:pi/180:pi

Regards

Best Answer

Related Solutions

MATLAB: Plotting a function with input and output

MATLAB: Is does the y axis of the graph have the same value all the way down

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