MATLAB: Hi, i have 170x170x36, (i.e,rows=170,col=170,images=36),i need to divide 36 image into 4 equal halves and find max value in each halves, so that i will get 2x2x36 as a final result.

digital image processing

plz help me with matlab code

Best Answer

divided_Array = mat2cell(YourArray, [85 85], [85 85], 36);

Now divided_Array{1,1}, {1,2}, {2,1}, {2,2} all exist and you can take their max()

Related Solutions

MATLAB: Sir, i cant get u, divided_Array = mat2cell(thearray, [85 85], [85 85], 36);how to find max value for 4 halves in each image from that result

For any one block indexed at J, K,

max(max(divided_Array{J,K},1),2)

The result of this expression would be size 1 x 1 x 36 . You can put the parts together to get your final result.

MATLAB: Hi i have 1×36 cell,each cell contains 7×7 double, i need to divide each 7×7 equally into 4 halves and find max value in each halves,likewise for all 36 cells

yourcellarray = arrayfun(@(~) randi(20, 7), 1:36, 'UniformOutput', false)  %demo data
cellfun(@(m) cellfun(@(quadrant) max(quadrant(:)), ...  max of a quadrant
                     mat2cell(m, ...                    convert matrix in cell into cell of 4 quadrant
                              [ceil(size(m, 1)/2), floor(size(m, 1)/2)], ...
                              [ceil(size(m, 2)/2), floor(size(m, 2)/2)])), ...
        yourcellarray, 'UniformOutput', false) %process each cell

edit: removed the 'UniformOutput', false from the inner cellfun since it's actually not needed. The output is thus a 1x36 cell array of 2x2 matrix instead of a 1x36 cell array of 2x2 cell arrays of scalars.

Best Answer

Related Solutions

MATLAB: Sir, i cant get u, divided_Array = mat2cell(thearray, [85 85], [85 85], 36);how to find max value for 4 halves in each image from that result

MATLAB: Hi i have 1×36 cell,each cell contains 7×7 double, i need to divide each 7×7 equally into 4 halves and find max value in each halves,likewise for all 36 cells

Related Question