MATLAB: Help creating a for loop

for loopMATLABmatrixmatrix manipulation

I am taking some data in a 28×6 matrix and I am wanting to create a for loop that takes the value in each position in and divides that value by the sum of the entire row and then replace said value with that new calculated value. Then do this for each value in the matrix.

For example if I have the matrix:

[1 2 3 ; 4 5 6]

I would like to create a loop that makes the following matrix from the above matrix:

[(1/(1+2+3)) (2/(1+2+3)) (3/(1+2+3)) ; (4/(4+5+6)) (5/(4+5+6)) (6/(4+5+6))]

I am not sure how to go about this in a for loop and would appreciate the help.

Best Answer

M = [1 2 3 ; 4 5 6];
M ./ sum(M,2)

Note: this code requires R2016b or later. For earlier versions,

bsxfun(@rdivide, M, sum(M,2))

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MATLAB: How to remove repetition in matrix without changing length

with the size of your matrix, a brute force approach of generating a new permutation until it matches your requirement seems feasible. On the few test I did, it only took a maximum of 1 second:

%a better way to generate the original matrix:
numwords = 6;
numsounds = 6; %doesn't have to be the same number as numwords
wordperm = repmat(1:numwords, numsounds, 1);
wordsound = [wordperm(:), repmat([1:numsounds]', numwords, 1)];
%brute force search of random permutation with no two consecutive number in any column
tic
while any(any(diff(wordsound) == 0))
    wordsound = wordsound(randperm(numwords * numsounds), :);
end
toc
wordsound

MATLAB: Find sum of individual matrix of a given array of matrices and store it in a temporary array

Being M your matrix:

sol = sum(sum(M,3),2)

Best Answer

Related Solutions

MATLAB: How to remove repetition in matrix without changing length

MATLAB: Find sum of individual matrix of a given array of matrices and store it in a temporary array

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