MATLAB: Gradient command producing multiple functions

gradientmultiple functionsquiver

Hello, when I use the gradient command I am given multiple functions as the answer. I assume these are the gradient at each 'root'. Is it necessary to substitute X at a specific position to generate the gradient at the position? Furthermore, will quiver generate the slope field?

Best Answer

The functions you obtain from the gradient function are the derivatives with respect to the vector of the used variables. See https://www.mathworks.com/help/symbolic/gradient.html .

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MATLAB: How to get fsolve return number of iterations

Okay. So it turns out it needs this;

   [x,fval,exitflag,output] = fsolve(fun,x0,options)
   output.iterations

you have to return fval and exitflag even if you dont use them.

MATLAB: Slope at defined co-ordinates

The gradient is simply the derivative, since yours is a univariate function. I would create a vectorized anonymous function from it, and use it as I would any other function:

dd_dx = @(x) (1303*x)/2500 - (4999*x.^2)/100000 + 25/2;

then call it as:

x = linspace(0, 10);
figure(1)
plot(x, dd_dx(x))
grid

Best Answer

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MATLAB: How to get fsolve return number of iterations

MATLAB: Slope at defined co-ordinates

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