MATLAB: Generate a cell with 10 elements

cell array; odd; even;

Hello,
I have the following assignment:
1.3 Generate a cell with ten elements. Each element is a vector of random length (between 1 and 10) containing ones if the length is odd and zeros if the length is even.
For which I've been given the following solution:
    NumofVec = 10;
    for 1 = 1:NumofVec;
        Vlen = floor(rand*10)+1;
        V{i} = ones (1, Vlen)*rem(Vlen,2);
    end
Could you please explain to me the meaning of the last two lines?
    Vlen = floor(rand*10)+1;
    V{i} = ones (1, Vlen)*rem(Vlen,2);
Thanks a lot!
Massive thanks to anyone attempting to help!!
Silvi

Best Answer

my solution would be:
vlen=randi(10,[10,1])
V=arrayfun(@(x) (mod(x,2)*ones(x,1)),vlen,'UniformOutput',false)
Now the codes that you asked:
Vlen = floor(rand*10)+1;
rand generates a random number between 0 and 1. multiplying by 10 result into a random number between 0 and 10. floor rounds it down so 9.85 becomes 9. so floor(rand*10) generates a number between 0 and 9; hence adding 1 to generate a random number between 1 and 10.
ones (1, Vlen) generates a vector of length Vlen and all elements being one rem(Vlen,2) gives 0 if Vlen is even and gives 1 if Vlen is odd. So that line generates a vector of length Vlen and all the elements would be 1 if Vlen is odd;otherwise, the elements would be 0.
The two line code that I give you at the beginning would do the same thing.
vlen=randi(10,[10,1]) generates 10 random number between 1 and 10.
arrayfun applies (mod(x,2)*ones(x,1)) on each element of Vlen, with x being each element of glen. mod(x,2) again is zero if x is even and it is one if x is odd and ones(x,1) generates a vector of length x.
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