MATLAB: From Hz to radiant

cosdimensionhzMATLABradianssin

Hi everyone, this is a simple one.

Is the argument coorrect in this code?

gammaT_max = 0.8;
gammaT_min = 0.65;
f=50;%hz
w=f*6.28; %rad/s
A = (gammaT_max - gammaT_min)/2; %ampiezza
b = gammaT_max - ((gammaT_max - gammaT_min)/2);
gammaT = A*sin(w*z(2))+b

I just want to make sure the dimensions are ok. It should be fine, but I am not sure.

I have Matlab 2014b

Best Answer

Yes, though it would be more elegant to use 2*pi instead of 6.28.

Related Solutions

MATLAB: Problem with a function

You have defined gammaT as a variable that you multiply by, but it needs to be a function of time. You will likely need something like

gammaT = @(t) A*sin(w*t)+b
dz(1)=(1/(4*B*B*Lc))*(z(2)-gammaT(SOMETHING)*(z(1))^0.5);

The SOMETHING would have to be replaced with your time variable, but it is not obvious that you have a time variable. Perhaps v is your time variable.

MATLAB: Help in writing a function

‘which is obviously wrong since gammaT = @(t) A*sin(w*t)+b shoouldn't be define this way.’

Why? It appears to be coded correctly with respect to the posted image. It’s being evaluated with respect to your independent variable ‘v’, that appears to be correct. If it should actually be a different variable (such as time), it would be necessary to define the time in the context of the existing variables. We would need more information in order to help you with that.

For what it’s worth, the function runs without error for me using:

parameters = rand(8,1);

and:

[V,Z] = ode45(@(v,z)control1(v,z,parameters), [0 10], rand(2,1));
figure
plot(V, Z)
grid

Best Answer

Related Solutions

MATLAB: Problem with a function

MATLAB: Help in writing a function

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