MATLAB: FPLOT, how to define step size along X-axis

fplot step sizeMATLAB

I try to understand the possibilities of FPLOT and consulted the documentation (relevant phrases cited below). But I don´t understand how the step size along the X-axis, for which the Y values are then calculated, becomes automatically defined or can be manually defined.
On page 17-21 in the MATLAB R2013b Programming Fundamentals documentation it is given an example which makes use of FPLOT:
s = @(x) sin(1./x);
range = [0.01,0.1];
fplot(s,range)
In the documentation for the FPLOT function (help fplot) I then find this:
fplot(FUN,LIMS,N) with N >= 1 plots the function with a minimum of N+1 points. The default N is 1. The maximum step size is restricted to be (1/N)*(XMAX-XMIN).
[X,Y] = fplot(FUN,LIMS,…) returns X and Y such that Y = FUN(X)
NOW MY OBSERVATION: If coding the following:
s = @(x) sin(1./x);
range = [0.01,0.1];
[axisX,axisY]= plot(s,range)
then I receive for the X-axis 377 values registered. While MATLAB decided that the function should be plotted based on 377 calculated steps, I for instance would like it to become calculated in the given range in 20 steps along the X-axis and therefore tried to type:
clear axisX axisY;
[axisX,axisY]=fplot(s,range,20)
But I again receive 377 values registered, but not as expected only 20. Could you explain me, how the step size along the X-axis, for which the Y values are then calculated, becomes automatically defined or can be manually defined within/by the FPLOT syntax?

Best Answer

To define your own points, you could just use the feval function. You could define your own input vector (with say, 20 steps) and compute an output with an equal number of elements. From there, you can just plot the results!
Taking your example:
% Function to plot
s = @(x) sin(1./x);
% Defining values over which to evaluate the function
numPoints = 20;
xvec = linspace(0.01,0.1,numPoints);
% Evaluate via 'feval' and plot
yvec = feval(s,xvec);
plot(xvec,yvec)
Hopefully this helps to get you started!
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