Hello everyone,
Is there a way to force matlab to "resolve" a handle depending on a handle by replacing the "subhandle" by its expression?
Let me explain on a simple example. Say I define
>> f = @(x) x^2;>> g = @(x) f(x) + 1;
Now if I type g matlab returns
g =
function_handle with value:
@(x)f(x)+1
Is there an instruction I can use to force matlab to replace f(x) by x^2 in the expression of g, and return
g =
function_handle with value:
@(x)x^2+1
?
Thank you for reading,
Nil
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