I'm referring to this question:
How can I add grid to the figure which is not covered by the patch color?
MATLAB: Force grid to be on top of patch
figuregridpatch
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The gridlines can be put on top of the figure, and you can also vary the transparency of the grid lines.
Example —
x = 1:10;y = rand(2, 10);figuresubplot(2,1,1)patch([x fliplr(x)], [y(1,:) fliplr(y(2,:))+1], 'r', 'FaceAlpha', 0.3)Ax = gca;Ax.YGrid = 'on';Ax.GridAlpha = 0.5;subplot(2,1,2)patch([x fliplr(x)], [y(1,:) fliplr(y(2,:))+1], 'r', 'FaceAlpha', 0.3)Ax = gca;Ax.YGrid = 'on';Ax.Layer = 'top';Ax.GridAlpha = 0.5;EDIT —
Added plot image
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fig = figure();ax1 = axes('Parent', fig);[X, Y] = meshgrid(1:50, 1:60);Z = X.^2 + Y.^2 - cos(X.*Y);surf(ax1, X, Y, Z, 'edgecolor', 'none');ax2 = axes('Parent', fig, 'color', 'none', 'gridalpha', 1);linkprop([ax1 ax2], {'Position', 'XLim', 'YLim', 'ZLim', 'View'});grid(ax2, 'on');
Here the grid is on top of the surface. It is a bit difficult to tell that it is not the case that the surface is transparent with the grid below it, but in that case the grid would not appear as dark as it does here.
I would add a surface to this drawing, which would be a transparent grid, that is, the holes in the grid are transparent, and not the grid itself
You would not be able to do that just by using "grid on": there is a single grid alpha that is for the entire grid, with no way to make it selective. You would therefore have to draw the grid, such as using a surface or patch. For example surface with 'EdgeAlpha', 'interp' and 'AlphaData' being a 2D array the same size as ZData.
If you use that, then you do not need two axes: you can use a single axes with SortOrder set to 'childorder' https://blogs.mathworks.com/graphics/2014/11/04/sortmethod/
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